bash to merge lines in a file

I want convert this text:
/dev/mapper/sys-home   58G   26G   30G  47% /home
/dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /tmp
/dev/mapper/sys-home   58G   26G   30G  47% /usr
/dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /var
/dev/mapper/sys-home   58G   26G   30G  47% /lib
/dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /etc

to this one: /dev/mapper/sys-home   58G   26G   30G  47% /home /dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /tmp /dev/mapper/sys-home   58G   26G   30G  47% /usr /dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /var /dev/mapper/sys-home   58G   26G   30G  47% /lib /dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /etc

I have used

cat FILE |sed 'N;s/.com\n//'

Is there anyway to achieve this, or should I just write the If... Then...

Thanks everybody for the answers :D (you always show me new things :D)


The answer by potong is almost correct; it only handles one server, rather than multiple servers, but the change required is small.

$ sed -e '/^[^ ]*$/{h;d;}' -e 'G; s/\(.*\)\n\(.*\)/\2 \1/' data /dev/mapper/sys-home   58G   26G   30G  47% /home /dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /tmp /dev/mapper/sys-home   58G   26G   30G  47% /usr /dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /var /dev/mapper/sys-home   58G   26G   30G  47% /lib /dev/mapper/sys-tmp   3.9G  2.3G  1.5G  61% /etc

The script is in two parts, identified by the two -e options. The first part identifies server names; those lines contain no spaces (hence /^[^ ]*$/ looks for a line with no spaces), and copies the line into the hold space (h) and then deletes it (d) and continues with the next line. The second part of the script is only exercised on lines that contain spaces. It appends the content of the hold space to the pattern space after a newline (G); then it splits the line into 'everything up to the newline' and 'everything after the newline', and switches them so that the 'after' (\2) comes first, then a space, then the 'before' (\1).

This uses the classic sed regular expressions; it was tested on Mac OS X (10.7.5) with both the BSD sed and also with GNU sed without change. GNU sed has options such as -r to change the interpretation of regexes which would save you a few backslashes.

I don't know much about sed, but in AWK:

awk 'NR==1{prefix=$0;next} {print prefix, $0}' file

If that is the case, look for lines with only one field (column), use it for prefix. That means, the only change to the above script is NF (number of fields) in place of NR (number of records, or lines).

awk 'NF==1{prefix=$0;next} {print prefix, $0}' file

This might work for you (GNU sed):

sed -r '1{h;d};G;s/(.*)\n(.*)/\2 \1/' file
  • 1{h;d} save the first line in the hold space (HS) and then delete the pattern space (PS).
  • G on all subsequent lines append a newline and the HS to PS.
  • s/(.*)\n(.*)/\2 \1/ re-arrange the PS and remove the introduced newline.

Since posting the answer the original question was changed, to take this into account:

sed -r '/%/!{h;d};G;s/(.*)\n(.*)/\2 \1/' file

This handles multiple servers by saving lines in the HS which do not contain %.

try this one:

awk '!/^\/dev/{header=$0;next} {print header, $0}' input.txt

alternatively (functionally identical, but a bit easier to read and understand, IMO):

awk '{if($0 !~ /^\/dev/){header=$0}else{print header, $0}}' input.txt

awk '{if($0~/{x=$0}else{print x,$0}}' your_file

tested here

Another way using awk is as follows:

awk '{if ($1 ~ /{a= $0 } if ($1 ~ /dev/){ print a" "$0}}' temp.txt

  1. a = $0 copies the line to a if that contains
  2. If second lines contains /dev then it joins both lines

or other variation of potong sed

sed -re '/{h;d};G;s/(.*)\n(.*)/\2 \1/' temp.txt

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