Perl using $1 in a substitution replacement with variable interpolation

I am trying to use variable interpolation in a replacement string including $1, $2,... However, I can't get it to expand $1 into the replacement. I eventually will have the $pattern and $replacement variables be read from a configuration file, but even setting them manually doesn't work.

In the example script, you can see that the $1 (which should be 'DEF') is not expanded in $new_name, but it is in $new_name2 (without variables).

Adding an 'e' flag to the substitution doesn't help.

How do I fix this?



use strict;

my $old_name = 'ABC_DEF_GHI';

my $pattern = 'ABC_(...)_GHI';
my $replacement = 'CBA_${1}_IHG';

# using variables - doesn't work
my $new_name = $old_name;
$new_name =~ s|$pattern|$replacement|;

printf("%s --> %s\n", $old_name, $new_name);

# not using variables - does work
my $new_name2 = $old_name;
$new_name2 =~ s|ABC_(...)_GHI|CBA_${1}_IHG|;

printf("%s --> %s\n", $old_name, $new_name2);




You need to do this changes in your code:

my $replacement = '"CBA_$1_IHG"';  #note the single and double quotes
# ...
$new_name =~ s|$pattern|$replacement|ee;  #note the double "ee", double evaluation

See this SO answer for more information

/e treat $replacement as Perl code. The Perl code $replacement simply returns the value it contains.

If you want to evaluate the contents of $replacement as Perl code, you need

s/$search/ my $s = eval $replacement; die $@ if $@; $s /e

which can be written as


Note that since $replacement is expected to contain Perl code, it means that this can be used to execute arbitrary Perl code.

A better solution is to realise you are writing your own subpar templating system, and use an existing one instead. String::Interpolate understands the templating syntax you are currently using:

use String::Interpolate qw( interpolate );
s/$search/interpolate $replace/e

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