Calling overloaded operator function from struct pointer

I have the following struct in C++

struct Jam
    void operator()()
        cout << "Test";

And I am able to call the overloaded function like so:

Jam j;

But I was wondering what the proper way to call the function from a pointer to the same struct. For example if I have:

Jam *j = new Jam;

I receive errors telling me it needs a function name. Is this possible? Thanks!


The easiest and clearest way is to dereference the pointer:


Alternatively, you can use the -> syntax with the function's name (which is operator()):


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