# Replacing an element from list after checking for condition in python: doing it the “pythonic way”

I have a list of numbers such as:

```a = [2,4,5,12]
```

I want to change the list by subtracting 10 from any element that is greater than 10.

I can do the following for that:

```i = 0
for ax in a:
if ax>10:
ax = ax-10
a[i] = ax
i = i+1
```

But this is not a "pythonic" way of coding. I would be fine with this loop if I was using Fortran but Python is better than these structured loops.

Can I do this in another way?

A very pythonic way is to use a list comprehension with a conditional expression:

```>>> a = [2,4,5,12]
>>> a = [x-10 if x > 10 else x for x in a]
>>> a
[2, 4, 5, 2]
>>>
```

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