# BCD Hex String to Integer

I was able to modify the solution provided by Brad Christie to get the results I am expecting for the Hours, Minutes, Seconds, Months, Days, and Years all of which are in BCD Format:

static Int32 GetYearFromBCD(Int32 time) { int length = time.ToString().Length -1; List<Int32> YearList = new List<Int32>(); for (Int32 i = length; i >= 0; i --) { Int32 place = i * 4; Int32 val = 0x01 << place; Int32 curVal = (Int32)(time / val); if (curVal > 9 && YearList.Count > 0) { Int32 delta = (Int32)(curVal / 10); YearList[YearList.Count - 1] += delta; curVal -= delta * 10; } YearList.Add(curVal); time -= curVal << place; } Int32 Year = 0; for (Int32 y = 0; y < YearList.Count; y++) Year += YearList[y] * (Int32)Math.Pow(10,(length+1 - y)-1); return Year; }

I wanted to provide an update to this question. After the device was running for several days through New Years, I was able to full confirm that the code solution Brad posted does exactly what we will need.

I was able to confirm my suspicions that the expected value was indeed a Binary Coded Decmial, I was able to confirm that the value expected only works has a HEX value. A co-worker was able to independently confirm the time and date, using table for the standard, so I feel comfortable putting this to bed.

I was able to confirm that for whatever reason the decmial value of the data does not work, I can only conclude the data is being sent as a hex value by the device, my only concern is will other applications work in a similar method.

I appreciate everyone's help in figuring this out, some of the comments lead me down a path that allow me to figure out.

## Answers

Well, even though the numbers don't seem to make sense, this is what I came up with (giving the results *you're* expecting (from the examples provided). Take this through the wringer and see if it comes out with all the results you are expecting:

static Int32 GetYearFromBCD(Int32 time) { List<Int32> YearList = new List<Int32>(); for (Int32 i = 3; i >= 0; i --) { Int32 place = i * 4; Int32 val = 0x01 << place; Int32 curVal = (Int32)(time / val); if (curVal > 9 && YearList.Count > 0) { Int32 delta = (Int32)(curVal / 10); YearList[YearList.Count - 1] += delta; curVal -= delta * 10; } YearList.Add(curVal); time -= curVal << place; } Int32 Year = 0; for (Int32 y = 0; y < 4; y++) Year += YearList[y] * (Int32)Math.Pow(10,(4 - y)-1); return Year; }

I'm really just taking a shot in the dark at this as the numbers you gave aren't what I would call typical. Having said that, you have to make what you're receiving work, so :shrug:.

If you want to convert number to hex representation just use ToString with "x" as param:

2010.ToString("x") output: "7da"

However, I don't really understand what to you want to achieve if you say that for 2010, you expect 200A.

Are you really sure that your example is correct? Why do you have a hex-number, where the first part is with base 10 and the second part is base 16?

*Normal* would one of these:

- 2010 => 0x07DA
- complete hex

- 2010 => 0x140A
- the number is broken half-way and each part is hex

- 2010 => 0x2010
- bcd encoded as found on wikipedia (where else) ;-)

After some googling and thinking here is my first idea:

- Put everything into an BinaryReader.
- Get all values individually out of it by calling BinaryReader.ReadByte() and cast it to an int
- Multiply each value first by 10, then divide by 16
- Put all of this individual values into a List<int>
- use Math.Pow(value, 10 * (List.Count - indexOfValue)) to aggregate all these values

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