GTK Timer - How to make a timer within a frame

How do g_timer_new works?

is it possible to do a

char timerz[50];

GTimer *timer

g_timer_start(GTimer *timer);

strcpy(timerz,(g_timer_elapsed(GTimer *timer))

Or what Could I do to have a timer in a gtk_frame???

Have a nice day! :D


You can use g_timeout_add or g_timeout_add_seconds which will call a timeout function at regular interval. Please note that this timeout function can be delayed due to event processing and should not be relied on for precise timing. Check this developer page for more info on main loop. Here is an example to get you started (you can improvise over this). In the example the timeout is set in seconds thus using g_timeout_add_seconds, use g_timeout_add if you need millisecond precision.

#include <stdio.h>
#include <string.h>
#include <gtk/gtk.h>

/* Determines if to continue the timer or not */
static gboolean continue_timer = FALSE;

/* Determines if the timer has started */
static gboolean start_timer = FALSE;

/* Display seconds expired */
static int sec_expired = 0;

static void
_quit_cb (GtkWidget *button, gpointer data)
    (void)button; (void)data; /*Avoid compiler warnings*/

static gboolean
_label_update(gpointer data)
    GtkLabel *label = (GtkLabel*)data;
    char buf[256];
    memset(&buf, 0x0, 256);
    snprintf(buf, 255, "Time elapsed: %d secs", ++sec_expired);
    gtk_label_set_label(label, buf);
    return continue_timer;


static void
_start_timer (GtkWidget *button, gpointer data)
    (void)button;/*Avoid compiler warnings*/
    GtkWidget *label = data;
        g_timeout_add_seconds(1, _label_update, label);
        start_timer = TRUE;
        continue_timer = TRUE;

static void
_pause_resume_timer (GtkWidget *button, gpointer data)
    (void)button;/*Avoid compiler warnings*/
        GtkWidget *label = data;
        continue_timer = !continue_timer;
            g_timeout_add_seconds(1, _label_update, label);
            /*Decrementing because timer will be hit one more time before expiring*/

static void
_reset_timer (GtkWidget *button, gpointer data)
    (void)button; (void)data;/*Avoid compiler warnings*/
    /*Setting to -1 instead of 0, because timer will be triggered once more before expiring*/
    sec_expired = -1;
    continue_timer = FALSE;
    start_timer = FALSE;

int main(void)
    GtkWidget *window;
    GtkWidget *vbox;
    GtkWidget *start_button;
    GtkWidget *pause_resume_button;
    GtkWidget *reset_button;
    GtkWidget *quit_button;
    GtkWidget *label;

    gtk_init(NULL, NULL);
    window = gtk_window_new(GTK_WINDOW_TOPLEVEL);
    g_signal_connect (G_OBJECT (window), "destroy", 
                    G_CALLBACK (gtk_main_quit),
    vbox = gtk_vbox_new (FALSE, 2);
    gtk_container_add(GTK_CONTAINER(window), vbox);

    label = gtk_label_new("Time elapsed: 0 secs");

    start_button = gtk_button_new_with_label("Start");
    g_signal_connect(G_OBJECT(start_button), "clicked", G_CALLBACK(_start_timer), label);

    pause_resume_button = gtk_button_new_with_label("Pause/Resume");
    g_signal_connect(G_OBJECT(pause_resume_button), "clicked", G_CALLBACK(_pause_resume_timer), label);

    reset_button = gtk_button_new_with_label("Reset");
    g_signal_connect(G_OBJECT(reset_button), "clicked", G_CALLBACK(_reset_timer), label);

    quit_button = gtk_button_new_with_label("Quit");
    g_signal_connect(G_OBJECT(quit_button), "clicked", G_CALLBACK(_quit_cb), NULL);

    gtk_box_pack_start (GTK_BOX(vbox), label, 0, 0, 0);
    gtk_box_pack_start (GTK_BOX(vbox), start_button, 0, 0, 0);
    gtk_box_pack_start (GTK_BOX(vbox), pause_resume_button, 0, 0, 0);
    gtk_box_pack_start (GTK_BOX(vbox), reset_button, 0, 0, 0);
    gtk_box_pack_start (GTK_BOX (vbox), quit_button, 0, 0, 0);


    g_timeout_add_seconds(1, _label_update, label);
    continue_timer = TRUE;
    start_timer = TRUE;

    return 0;

Hope this helps!

Need Your Help

Android Bitmap.getPixel always returns negative

android bitmap android-imageview getpixel

I am a newbie using Android and have been really working on this problem for four days now. I would really appreciate someone's help.